(2x^2-5x-7)(x-1)=0

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Solution for (2x^2-5x-7)(x-1)=0 equation:


Simplifying
(2x2 + -5x + -7)(x + -1) = 0

Reorder the terms:
(-7 + -5x + 2x2)(x + -1) = 0

Reorder the terms:
(-7 + -5x + 2x2)(-1 + x) = 0

Multiply (-7 + -5x + 2x2) * (-1 + x)
(-7(-1 + x) + -5x * (-1 + x) + 2x2 * (-1 + x)) = 0
((-1 * -7 + x * -7) + -5x * (-1 + x) + 2x2 * (-1 + x)) = 0
((7 + -7x) + -5x * (-1 + x) + 2x2 * (-1 + x)) = 0
(7 + -7x + (-1 * -5x + x * -5x) + 2x2 * (-1 + x)) = 0
(7 + -7x + (5x + -5x2) + 2x2 * (-1 + x)) = 0
(7 + -7x + 5x + -5x2 + (-1 * 2x2 + x * 2x2)) = 0
(7 + -7x + 5x + -5x2 + (-2x2 + 2x3)) = 0

Combine like terms: -7x + 5x = -2x
(7 + -2x + -5x2 + -2x2 + 2x3) = 0

Combine like terms: -5x2 + -2x2 = -7x2
(7 + -2x + -7x2 + 2x3) = 0

Solving
7 + -2x + -7x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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